Homework 4 - part A

ECE 4339
Han Q. Le (copyrighted) U. of Houston

In the following, you are welcome to use the APPs included to verify your answer, but you must show your work.

1. Carbon dating

We heard about carbon dating: archeologists determine the ages of ancient objects by measuring the ratio of carbon 14 vs. carbon 12. You can search the Internet about it, but below is a short but very useful link to read:
ECE 4339_S_2015_HW_4A_1.gif
Below is from the website: http://hyperphysics.phy-astr.gsu.edu/hbase/nuclear/cardat.html
ECE 4339_S_2015_HW_4A_2.gif

In the example above, if we see ECE 4339_S_2015_HW_4A_3.gif in a piece of wood is 50% of present value, the wood is 5,730 yr old, and so on. We found an ancient remain with 32% of ECE 4339_S_2015_HW_4A_4.gif relative to the present value, how old is that material?

APP: carbon dating

2. Moore’s law

Gordon Moore stated that “The number of transistors incorporated in a chip will approximately double every 24 months.”
http://www.intel.com/content/www/us/en/history/museum-gordon-moore-law.html

Starting from 1970 with chip just ~ thousand transistors, in 40 years, we have 1,000,000,000 transistor chips by 2010. Apply Moore’s law, approximately what year did we have 500,000,000 transistor chips?

3. Moore’s law again

Watch APP How to find an exponential coefficient below to get help.

Moore’s law graph

ECE 4339_S_2015_HW_4A_6.gif

Work directly on the chart above (by drawing a best fit straight line), obtain the period for which the transistor count is double on a chip based on your best fit straight line and not from Moore’s statement. Show the value of the best-fit-line slope from which you derive the chip double period (this is the opposite of the half-life of carbon 14). Watch APP below if needed.

APP: How to find an exponential coefficient with the slope of a semilog plot

According the to data above, if you invested $10,000 in Apple in 2001, how much do you have now?

4. Interest and interest rate

You borrow $20,000 from a bank to buy a car with an annual interest rate of 6%, but is compounded monthly. You don’t have to pay for the first 3 years. Starting on the 4th years (after 36 months), how much do you owe the bank on the car loan?

APP: Loan or Investment yield

5. Mortgage

You borrow $24,000 from a bank to buy a car with an annual interest rate of 6%, compounded monthly. You pay back monthly M amount. What value is the value of M such that you pay off in 60 months? You can solve by doing the below:

5.1

Let P[n] be your outstanding principal after the ECE 4339_S_2015_HW_4A_9.gif month of the loan. What is P[n+1] immediately after you make your monthly payment?

5.2

Derive a recursive formula to obtain an expression for P[n] based on P[0], interest rate r, and monthly payment M.

5.3

Solve for M by setting P[N]=0 where N is 60 (month).

5.4

What is the total amount of interest you pay over the lifetime of the loan?

HELP: APP: Mortgage calculator

APP: Mortgage calculator

6. Interest and investment

See APP Loan or Investment yield in problem 4 above.

6.1 Investment in SP500

Suppose that 3 yr ago (March 2012), you borrow $20,000 with an annual interest rate of 6%, compounded monthly, but not to buy anything. Instead, you invest in an index fund that tracks SP500. After 3 years, the value of your investment is shown by the blue line below: it has a 14% annual rate of yield, but compounded continuously. Did you make a profit or lose money? and how much?

ECE 4339_S_2015_HW_4A_11.gif

6.2 Investment in NASDAQ

If, instead investing in SP500, suppose you invested in a NASDAQ fund instead, which has an 18% annual return rate (compounded continuously, of course) as shown below. How much profit or loss would you make with the $20,000 loan?

ECE 4339_S_2015_HW_4A_12.gif

6.3 Long term investment

Suppose that the annual return rate is 18% (compounded continuously) is going on for many many years. How long will it take for your initial investment of $20,000 to become $1,000,000?

7. Electron and other particle lifetime

7.1 Electron population vs. time. (answer given)

In a semiconductor, excess electrons have a lifetime of 1.5 ns, write an expression (a mathematical formula) for its population as a function of time.

Answer

Its population can be described as:       ECE 4339_S_2015_HW_4A_13.gif
where ECE 4339_S_2015_HW_4A_14.gif is the population at time t=0, and τ=1.5 ns

7.2 Electron half-life

What is the electron half-life? (which is the time for which the population is reduced to half of the original)

7.3 Carbon 14 life-time

The half-life of carbon 14 is 5,370 yrs, can carbon 14 population be described with a formula like in 7.1? What is its lifetime τ?

7.4 Dirty bomb

A dirty bomb is also called RDD (a Radiological Dispersal Device, see here: http://www.remm.nlm.gov/rdd.htm or here:  http://www.nrc.gov/reading-rm/doc-collections/fact-sheets/fs-dirty-bombs.html).
Several radioactive materials can be used. Calculate how it will take for a contaminated area to have its radioactive material reduced to 1% of its original amount for the following isotopes with given 1/2-life:
Cobalt-60: 5.27 years
Strontium-90: 28.79 years
Caesium-137: 30.17 years

7.5 Nuclear accident

Suppose a nuclear accident happens and an amount of plutonium-238 (HL=87.7 years) is spewed. A measurement indicates that the amount in the contaminated area must be reduced by a factor of 200 to be safe. How long will it take for the area to be safe again?

8. Technology adoption

8.1 Early technology adopter exponential model

Below is the data of smartphone quarterly shipment as a function of time. What is the annual growth rate of smart phone shipment over a 4-yr period from 2009 to 2012? You can answer the question by plotting the data on a semilog scale from Q1:09 to Q4:12 (4-year period). From the log scale, determine the annual adoption growth rate.
(see APP  How to find an exponential coefficient  in Problem 3 for help).

ECE 4339_S_2015_HW_4A_16.gif

8.2 Note: Early adoption growth model

Read for information and to review Fermi-Dirac distribution shape, no need to do anything.

Early adoption growth tends to be exponential and the later trend is saturation (when everyone already has enough!). The behavior is very common throughout human history and the curve to describe it is call sigmoid curve (S-curve, etc.) , which is mathematically very similar to or of the same form as Ferm-Dirac distribution (reverse for growth)

ECE 4339_S_2015_HW_4A_17.gif   

ECE 4339_S_2015_HW_4A_18.gif

APP: Sigmoid curve of new practice adoption and exponential growth model of early adopters

Fermi distribution for comparison

8.3 New technology adoption

Pick 2 technologies in APP Sigmoid model fit for technology adoption of American households (below),fit with the S-curve to obtain mean time to adoption and the adoption annual growth rate.

APP: Sigmoid model fit for technology adoption of American households

ECE 4339_S_2015_HW_4A_22.gif

9. Human mobility and diffusion length

See APP  How to find an exponential coefficient in problem 3 above for help.

Refer to this paper:

http://www.nature.com/srep/2013/131018/srep02983/full/srep02983.html#close

ECE 4339_S_2015_HW_4A_23.gif

ECE 4339_S_2015_HW_4A_24.gif

ECE 4339_S_2015_HW_4A_25.gif

The blue solid lines denote the actual traveling distance distributions. The red triangles represent the trip-length distributions simulated by our model. (a)Beijing. (b)London. (c)Chicago. (d)Los Angeles.

9.1 Human “diffusion length”

If we treat the probability for trip length as a representative of “human diffusion” capability tendency (how far we can travel given our finite time and resource constraint), calculated the “human diffusion length” of the four given cities (Beijing, London, Chicago, Los Angeles) based on the given data. Write an expression of P[d] as a function of d, given that:
                                      ECE 4339_S_2015_HW_4A_26.gif  (or: ECE 4339_S_2015_HW_4A_27.gif , here, x or d is just a dummy variable)

See APP  How to find an exponential coefficient in problem 3 above for help.

9.2 Human mobility

If we assume that the probability for trip length is determined by human’s available time T and resource for travel, which also obeys an exponential distribution                       ECE 4339_S_2015_HW_4A_28.gif
where ECE 4339_S_2015_HW_4A_29.gif is the mean time of travel, we can assume that people, regardless where they live, budget approximately the same amount of time for travel, just like people have approximately the same amount of time for working, consuming food, entertaining etc.
If that is the case, then the diffusion length depends on the average travel velocity which can be different for different cities, depending on the mean of mobility (automobile, bicyle, walking, etc.), the road infrastructure, the speed limit, the number of police enforcing the speed limit, etc. Let ECE 4339_S_2015_HW_4A_30.gif, what is the average travel speed for each city?

Additional reference:

Link

10. Solar system planet distribution

10.1 Solar system planet distance from the Sun

ECE 4339_S_2015_HW_4A_31.gif

Assign the following number for the planets:

Number Planet Distance from the Sun (Astronom. Unit)
1 Mercury 0.39
2 Venus 0.72
3 Earth 1
4 Mars 1.52
6 Jupiter 5.20
7 Saturn 9.54
8 Uranus 19.19
9 Neptune 30.11
10 Pluto 39.5

ECE 4339_S_2015_HW_4A_32.gif

Below is the linear plot of the planet distance from the Sun

ECE 4339_S_2015_HW_4A_33.gif

ECE 4339_S_2015_HW_4A_34.gif

Plot the same data but on Log plot. What can you conclude about the planet distance from the Sun? (Can you write a formula
                               ECE 4339_S_2015_HW_4A_35.gif
where ECE 4339_S_2015_HW_4A_36.gif is the distance of the ECE 4339_S_2015_HW_4A_37.gif planet from the Sun?)
(see:  http://www.astro.cornell.edu/academics/courses/astro201/bodes_law.htm)

Spikey Created with Wolfram Mathematica 9.0